Mysql 的rank 函数如何实现 表特征：mysql> select from test;+---+---+ | a | b | +---+---+ | 1 | 20 | | 1 | 21 | | 1 | 24 | | 2 | 20 | | 2 | 32 | | 2 | 14 | +---+---+ 6 rows in set (0.00 sec)现在，我们以a分组，查询b列最大的2个值。
mysql ；rank函数怎么用
转：
Mysql
的rank
函数如何实现
表特征：
mysql>
select
*
from
test;
+------+------+
|
a
|
b
|
+------+------+
|
1
|
20
|
|
1
|
21
|
|
1
|
24
|
|
2
|
20
|
|
2
|
32
|
|
2
|
14
|
+------+------+
6
rows
in
set
(0.00
sec)
现在，我们以a分组，查询b列最大的2个值。
这条sql要怎么写了？
1.创建表
Create
Table:
CREATE
TABLE
`sam`
(
`a`
int(11)
DEFAULT
NULL,
`b`
int(11)
DEFAULT
NULL
)
ENGINE=MyISAM
DEFAULT
CHARSET=utf8
2.插入模拟数据
INSERT
INTO
`sam`
VALUES
(1,10),(1,15),(1,20),(1,25),(2,20),(2,22),(2,33),(2,45);
+------+------+
|
a
|
b
|
+------+------+
|
1
|
10
|
|
1
|
15
|
|
1
|
20
|
|
1
|
25
|
|
2
|
20
|
|
2
|
22
|
|
2
|
33
|
|
2
|
45
|
+------+------+
3.SQL实现
select
a,b,rownum,rank
from
(select
ff.a,ff.b,@rownum:=@rownum+1
rownum,if(@pa=ff.a,@rank:=@rank+1,@rank:=1)
as
rank,@pa:=ff.a
FROM
(select
a,b
from
sam
group
by
a,b
order
by
a
asc,b
desc)
ff,(select
@rank:=0,@rownum:=0,@pa=null)
tt)
result
having
rank
<=2;
4.结果：
+------+------+--------+------+
|
a
|
b
|
rownum
|
rank
|
+------+------+--------+------+
|
1
|
25
|
1
|
1
|
|
1
|
20
|
2
|
2
|
|
2
|
45
|
5
|
1
|
|
2
|
33
|
6
|
2
|
+------+------+--------+------+
4
rows
in
set
(0.00
sec)2019-07-28
