求助mysql问题,取出mysql间隔小于5分钟的数据

=cg_tmp.dtime as ptime2,if(TIMESTAMPDIFF(MINUTE, @ptime,cg_tmp.dtime)
求助mysql问题,取出mysql间隔小于5分钟的数据
--一个语句还真想不出怎么做, --建一个临时表,把下面查出的数据保存在里面,按rank分组,having count(*)>1 ,找出记录数大于1的rank就是你要的记录 select name,dtime,rank,ptime,ptime2 from(select cg_tmp.*, @rownum :=@rownum + 1,if(TIMESTAMPDIFF(MINUTE, @ptime,cg_tmp.dtime)<5,@rank:=@rank ,@rank:=@rank+1) as rank,@ptime2:=cg_tmp.dtime as ptime2,if(TIMESTAMPDIFF(MINUTE, @ptime,cg_tmp.dtime)<5,@ptime=null,@ptime:=@ptime2) as ptime from(select * from `timerecord` order by dtime) cg_tmp,(select @rownum :=0 , @ptime := null ,@rank:=0,@rank2:=0,@ptime2 := null) a) result2014-11-16
我见其中包含这句:
if(TIMESTAMPDIFF(MINUTE, @ptime,cg_tmp.dtime)<5这里的5就是时间相差小于5分钟,后面有个小于号看到没
2014-11-15
mengvlog 阅读 42 次 更新于 2025-10-30 21:46:22 我来答关注问题0
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