python代码实现“今天是今年的第几天”**#代码如下:list_day_runnian=[0,31,29,31,30,31,30,31,31,30,31,30,31]year=int(input(‘输入年份:’))month=int(input(‘输入月份:’))day=int(input(‘输入日期:’))if1=month=12:if(year%400==0)or((year%4==0)and(year%100!=0)):pastmo 继...
用Python,计算键盘随机输入的年有多少天,例如2018有365天x=eval(input(''请输入年份:''))if(x%100==0):y=x%400 if(y==0):print(''366'')else:print(''365'')if(x%100!=0):z=x%4 if(z==0):print(''366'')else:print(''365'')纯手打请采纳 用Python,从键盘任意输入一...
???return?"{0}年{1}月有{2}天".format(year,?month,?m[int(month)-1])print(getdays())python判断某一年的某个月有多少天一三五七八十腊;三十一天永不差;四六九冬三十整;平年二月二十八;闰年二月把一加。转化为代码就是:y?=?int(input('请输入年份:'))m?=?int(input('请输入月份...
"""计算输入日期是当年的第几天"""days = [0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]if is_leap_year(year):days[2] = 29 months = [0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334]if month > 12 or month < 1:return "输入有误,请输...
31]计算截至当前月份的天数 if is_leap_year(year):current_days = sum(leap_year_days_in_month[:month - 1])else:current_days = sum(days_in_month[:month - 1])加上当前日期,得出总天数 total_days = current_days + day 输出结果 print(f"今天是今年的第 {total_days} 天。")